x^2+86x+12=0

Solution for x^2+86x+12=0 equation:

x^2+86x+12=0

a = 1; b = 86; c = +12;
Δ = b2-4ac
Δ = 862-4·1·12
Δ = 7348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7348}=\sqrt{4*1837}=\sqrt{4}*\sqrt{1837}=2\sqrt{1837}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-2\sqrt{1837}}{2*1}=\frac{-86-2\sqrt{1837}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+2\sqrt{1837}}{2*1}=\frac{-86+2\sqrt{1837}}{2}
$